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Articles: Science | Pythogorous Theorem - Nazeer
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ABC is a T(triangle) rt angled at B.
a b c are the sides. b is the hypotenuse.
To prove b' (b square)= a' + c'.
Draw the circumcircle to the T.
O be the circumcentre. AC is the diameter.
O is the midpoint of AC. Join BO.
BO is a median.
It divides the T into 2 equal Ts namely T ABO & T BOC.
A(area) of T ABO = T BOC.
sqrt{b+c/2.c/2.c/2.b-c/2} = sqrt{b+a/2.a/2.a/2.b-a/2}.
[b'-c']c' = [b'-a']a'.
[b'-c']/[b'-a'] = a'/c'.
Subtracting 1 from both sides,
b' = a' + c'
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