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Articles: Science
Pythogorous Theorem
- Nazeer
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ABC is a T(triangle) rt angled at B. a b c are the sides. b is the hypotenuse. To prove b' (b square)= a' + c'. Draw the circumcircle to the T. O be the circumcentre. AC is the diameter. O is the midpoint of AC. Join BO. BO is a median. It divides the T into 2 equal Ts namely T ABO & T BOC. A(area) of T ABO = T BOC. sqrt{b+c/2.c/2.c/2.b-c/2} = sqrt{b+a/2.a/2.a/2.b-a/2}. [b'-c']c' = [b'-a']a'. [b'-c']/[b'-a'] = a'/c'. Subtracting 1 from both sides, b' = a' + c'

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