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Articles: Time Pass | | 12-coin problem | |
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| a very good question... I got the answer struggling for half-an-hour...I really dont know I can post the answer or not... if otherwise I am sorry... the sequence is (1)divide into 2 groups of 6-6 and weigh any one group as 3-3 ..(2) weigh any one of the 3 which are odd and with standard ones ... remember the direction.. u get the oddman is lighter or heavier (3)once u find the final one of 3 and the type of diffect .. 1-1 weighing will give u the final answer...
Posted by: Ravi Kanth Yalamanchili At: 23, Jan 2004 4:32:38 PM IST
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