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EE MIND READER LO EMI LOGIC LEDANDI .... U WILL GET ALAWYS THE SAME SYMBOL ..BCOS U WILL ALWAYS GET U R FINAL ANS AS MULTIPLS OF NINE ONLY SO WILL GET SAME SYMBOL ALWAYS....

Posted by: Mr. Sanjeev Dev At: 25, May 2003 12:54:52 PM IST
take any two digit number,in which the digit in units place be "A" and the digit in units place is "B"(let) then (10*A + B ) - (A + B ) = 9*A which is a multiple of "9" and multiples of "9" anniti dhaggara same symbol vundhi....

Posted by: Raj Sekhar At: 25, May 2003 0:29:00 AM IST
its always the same answer..wait i am giving explanation...

Posted by: Raj Sekhar At: 25, May 2003 0:18:50 AM IST
Can anybody give the logic for mind reader??

Posted by: Mr. Spider Man At: 25, May 2003 0:08:00 AM IST
ok...i too tried very much..

Posted by: Raj Sekhar At: 25, May 2003 0:05:23 AM IST
Mind reader: How is it possible?? http://mr-31238.mr.valuehost.co.uk/assets/Flash/psychic.swf

Posted by: Mr. Spider Man At: 25, May 2003 0:04:36 AM IST
yeah.. i missed that..

Posted by: Mr. Spider Man At: 24, May 2003 11:49:31 PM IST
if the rough ball is in "D" group,then????

Posted by: Raj Sekhar At: 24, May 2003 11:35:55 PM IST
Divide the 12 balls into 4 batches of 3 each. Lets name them A,B,C and D. Weigh A against B and A against C. Now, you know which batch has the rouge ball and whether it is heavier or lighter than the other balls. Pick 2 of the balls from the rouge batch and weigh them. If they are equal, the 3rd ball in that batch is the rouge otherwise, you know which one is the culprit.

Posted by: Mr. Spider Man At: 24, May 2003 11:19:35 PM IST
You have twelve balls that weigh the same, except for one. This ball may be lighter or it may be heavier than the other eleven. You are given some scales to balance balls against each other. How do you discover the rouge ball, and whether it is heavier or lighter, with only three weighings ?

Posted by: Mr. Sanjeev Dev At: 24, May 2003 1:20:39 PM IST
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