|
|
|
General Forum: Love | | PUZZLES PUZZLES AND PUZZLES | |
| Heres one...
A box of candies can be equally divided by weight without cutting pieces between 3, 4 or 7 people.
Each candy is an integral number of ounces.
What is the least number of pieces of candy the box could contain? The candies may be of different weights.
Posted by: చంటోడు At: 12, Oct 2004 1:12:24 AM IST
an what abt subsets problem??? i think its a bit of out of topic..
so,anymore new questions???
Posted by: Raj Sekhar At: 12, Oct 2004 0:48:32 AM IST
thx RS saaru! :-)
Posted by: చంటోడు At: 12, Oct 2004 0:44:40 AM IST
Let 5 coins group contains "X" heads
7 coins group should contain "7-x" head
==> 7 coins group contains "X" tails
after flippping all the seven coins, "X" tails will become "X" heads in the 7 coins group
so,both the group contains "X" number of heads :)
Posted by: Raj Sekhar At: 12, Oct 2004 0:38:41 AM IST
woww...perfect....welldone paarthaa saaru :)
Posted by: Raj Sekhar At: 12, Oct 2004 0:35:24 AM IST
My solution for the 7heads/5tails puzzle...
1. Divide 12 coins into 2 groups of 7 and 5
2. Combinations you would get from this are
Gr-7...Gr-5
H/T....H/T
----------
7/0....0/5
6/1....1/4
5/2....2/3
4/3....3/2
3/4....4/1
2/5....5/0
3. From the above, pick the 7-coins group and flip all of them, then heads will be same as the 5-coins group!
Posted by: చంటోడు At: 12, Oct 2004 0:12:35 AM IST
:)
Posted by: Raj Sekhar At: 11, Oct 2004 6:22:25 PM IST
yup raj..:)
Posted by: Vijay At: 11, Oct 2004 5:29:27 PM IST
8.9 $
Posted by: Raj Sekhar At: 11, Oct 2004 10:28:20 AM IST
yooooooooooo.....solved the subsets problem..
hammayyaa...oka panaipoyindi...
Posted by: Raj Sekhar At: 9, Oct 2004 2:21:39 PM IST
| |
|
|
|
| Advertisements |
|
|
|
|
| Advertisements |
|
