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General Forum: Love | | PUZZLES PUZZLES AND PUZZLES | |
| clueless to paartha bilkul NAHI hai :)
Posted by: Raj Sekhar At: 28, Sep 2004 0:48:17 AM IST
lol RS, dont tell her, let her still think its me and get confused! :P
good luck to your bad luck RS, I havent tried it seriously yet! ;-)
Posted by: చంటోడు At: 28, Sep 2004 0:47:13 AM IST
Heyy priyzz...i was abt to ask u......u used to participate actively in this thread...now,not coming?? y??
and parthaa?? hehee......u really dont know????:))
Posted by: Raj Sekhar At: 28, Sep 2004 0:39:01 AM IST
And for the next question,
luck baagunte 3 weighings lo ayipotundi pani
badluck baagunte 5 tho cheyochcanukuntaa
Posted by: Raj Sekhar At: 28, Sep 2004 0:24:16 AM IST
ayyayyoo...konchem think cheyyaalsindi inkaa:(
Posted by: Raj Sekhar At: 28, Sep 2004 0:18:42 AM IST
/What is the smallest number such that if you move the last digit to the front (e.g. 123 to 312) you get a new number which is an integer multiple of the original number?/
Answer for this is : 102564
102564 x 4 = 410256
Sekhar, you were quite close to this!
Posted by: చంటోడు At: 28, Sep 2004 0:11:01 AM IST
righto RS Saaru! :-)
oh so you were looking for consecutive non-primes aa!
Ok, heres the last one for today (coz I want you to go and sleep after this :P)
And if you happen to solve it, pls just post that you solved it and leave it to the other ppl from India who are not so nocturnal...:P
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You have to sort five weights weighing 51g, 52g, 53g, 54g, and 55g. You have a balance scale with which you can compare the weights.
If the difference between two weights is greater than 1.5g, the scale will correctly determine which side is heavier. If the difference between the weights is less than 1.5g or equal, the scale will indicate the weights are equal.
Sort the weights in the smallest number of weighings.
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Posted by: చంటోడు At: 25, Sep 2004 3:56:31 AM IST
1,2,3,4,5,6
61,62,63,64,65,66.
First 1 year theesukoledu...so,61 prime number kaabatti answer raaledu......tharuvaatha striek ayyindi
Posted by: Raj Sekhar At: 25, Sep 2004 3:44:45 AM IST
cool, one more...
A boy and his grandpa have the same birthday. For 6 consecutive years the grandpa's age was an integer multiple of the boy's age, what were their ages then?
Posted by: చంటోడు At: 25, Sep 2004 3:30:44 AM IST
1,00,000 = 5^5 X 2^5
sum = 3125 + 32 = 3157
:)
Posted by: Raj Sekhar At: 25, Sep 2004 3:15:46 AM IST
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