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Another : Start with the number 7^1996. Strike the first (leftmost) digit from the number, and add that to the remaining number (e.g. if the current number is 4327892432423, the number at the next step would be 327892432427). Repeat this process until only 10 digits remain. Prove that the remaining 10-digit number has two equal digits.

Posted by: Raj Sekhar At: 5, Jan 2005 8:36:51 PM IST
hmm...Frank ..wehre r u?? ok,another small question.. Prove that the number between a twin primes is always divisible by 6 .

Posted by: Raj Sekhar At: 30, Nov 2004 7:14:03 PM IST
If p is prime , prove that there exists another prime number between p and 2p. Posted by: Mr. Frank Abagnale Jr. At: 7, May 2004 5:14:30 PM IST ????

Posted by: Raj Sekhar At: 3, Nov 2004 6:42:23 PM IST
Posted by: Blue Screen Of Death At: 9, Oct 2004 4:43:34 AM IST That right..ok..but it should be clear...like how can u say that... Any number is of the form 3k,3k+1 or 3k+2 (3k)^2 = 9k^2 and 9k^2 (mod 3) = 0 3k+1)^2 (mod 3) = 1 (3k+2)^2 (mod 3) = 1 In none of the three cases...u get 3k+2 and so.. Posted by: Blue Screen Of Death At: 9, Oct 2004 5:04:35 AM IST if a^2 = b^2 then abs(a) = abs(b) a = +/-(b) here 4 - 9/2 = -(5 - 9/2) ===> -(1/2) = -(1/2) which is true

Posted by: Raj Sekhar At: 9, Oct 2004 4:05:24 AM IST
given*

Posted by: Raj Sekhar At: 9, Oct 2004 2:19:06 AM IST
okk....give "none" is the answer...try to prove "how" and "why"

Posted by: Raj Sekhar At: 9, Oct 2004 2:17:41 AM IST
Unfortunately,or fortunately(?) "None" is the correct answer

Posted by: Raj Sekhar At: 9, Oct 2004 2:09:40 AM IST
??

Posted by: Raj Sekhar At: 9, Oct 2004 1:47:23 AM IST
Ok,Starting with simple one Find for what values of "N" (N ia a ntural number) (3*N + 2) is a perfect square of an integer ?

Posted by: Raj Sekhar At: 28, Sep 2004 0:56:49 AM IST
Just post yours RS, no harm if there are multiple unsolved ones after a sufficient time I guess! :-)

Posted by: చంటోడు   At: 28, Sep 2004 0:49:06 AM IST
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